HowTo deal with more struct members at same level with same id?

In a more detailed analysis of the original xmlstream I've recognized case described is not single! Also on level3 there is a similar repeation; something like:     [myStruct]       [level1] = "value1"         [level21] = "value21"         [level22] = "value22First"         [level22] = "value22Second"         [level23] = "value23"           [permission] = "value231"           [permission] = "value232"           [mapping] = "value238"           [mapping] = "value239"

Hi, my first opinion: - The original xmlstream could be considered correct having two members same level with same ID?YES - Should xmltostruct instruction generate at least a feedback? NO, what was in the XML is now in the struct so no problem here - Should assignment instruction generate at least a feedback? YES, it would be nice if there was a $status/$procerror for "requested value is not unique"   Obviously your statement  myField = myStruct->level1->level22 cannot give a result on this struct as it does not ask for a unique value. In order to get values from the non-unique members you would need to loop through the "children" of [level1].

Theo Neeskens said ... you would need to loop through the "children" of [level1].

Is that possible? To loop through ordered positions instead of using names? I am not aware of it... I've tried already to rename culprit nodes with: myStruct->level1->level22->$name = "level22a" but also $name is applied to all cases without any possibility to filter...

gianni said

Theo Neeskens said ... you would need to loop through the "children" of [level1].

Is that possible? To loop through ordered positions instead of using names? I am not aware of it...

Yes.   For example:  myField = myStruct->level1->level22{1} ; myField = "value22First"  myField = myStruct->level1->level22{2} ; myField = "value22Second"   Or you do this:  $1 = myStruct->level1->*{1} ; $1 = "value21"  $2 = myStruct->level1->*{1}->$name ; $2 = "level21"  $1 = myStruct->level1->*{2} ; $1 = "value22First"  $2 = myStruct->level1->*{2}->$name ; $2 = "level22"  $1 = myStruct->level1->*{3} ; $1 = "value22Second"  $2 = myStruct->level1->*{3}->$name ; $2 = "level22"   You could of course use a for loop to go through all the Struct nodes.   And if you would like to assign a value from a Struct to a field then you can check with the Struct function $isScalar if a Struct node is a scalar Struct (has a value).   if (myStruct->level1->level22->$isScalar)     myField = myStruct->level1->level22 else    message/info "myStruct->level1->level22 is not a scalar Struct node" endif   Hope this helps.   Regards, Daniel

diseli said

gianni said

Theo Neeskens said ... you would need to loop through the "children" of [level1].

Is that possible? To loop through ordered positions instead of using names? I am not aware of it...

Yes. ... Regards, Daniel

Oh oh...that's an eye opening news... Thanks a lot Daniel! I wandered through last ULibrary for a while but without finding any reference to these syntaxes...wondering why... Thanks again!

gianni said Oh oh...that's an eye opening news... Thanks a lot Daniel! I wandered through last ULibrary for a while but without finding any reference to these syntaxes...wondering why... Thanks again!

 You are welcome! But the stuff I've mentioned can also be found in the ULibrary. You start here:

• Programming in Uniface > Proc Language > Structs

And then you work your way through the sub-topics. The Struct access operators are described here:

• Programming in Uniface > Proc Language > Structs > Struct Access Operators:
  • Struct Index Operator ({N})
  • Struct Collection Operator (->*)

Also interesting:

• Programming in Uniface > Proc Language > Structs > Working with Structs
• Programming in Uniface > Proc Language > Structs > Working With Structs: Code Examples

And in case you are bored: WebEx: Structs In Uniface Hope this helps. Kind regards, Daniel